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6x^2+48x-120=0
a = 6; b = 48; c = -120;
Δ = b2-4ac
Δ = 482-4·6·(-120)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-72}{2*6}=\frac{-120}{12} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+72}{2*6}=\frac{24}{12} =2 $
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